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diff --git a/Documentation/memory-barriers.txt b/Documentation/memory-barriers.txt new file mode 100644 index 000000000..f95746189 --- /dev/null +++ b/Documentation/memory-barriers.txt @@ -0,0 +1,3064 @@ + ============================ + LINUX KERNEL MEMORY BARRIERS + ============================ + +By: David Howells <dhowells@redhat.com> + Paul E. McKenney <paulmck@linux.vnet.ibm.com> + +Contents: + + (*) Abstract memory access model. + + - Device operations. + - Guarantees. + + (*) What are memory barriers? + + - Varieties of memory barrier. + - What may not be assumed about memory barriers? + - Data dependency barriers. + - Control dependencies. + - SMP barrier pairing. + - Examples of memory barrier sequences. + - Read memory barriers vs load speculation. + - Transitivity + + (*) Explicit kernel barriers. + + - Compiler barrier. + - CPU memory barriers. + - MMIO write barrier. + + (*) Implicit kernel memory barriers. + + - Locking functions. + - Interrupt disabling functions. + - Sleep and wake-up functions. + - Miscellaneous functions. + + (*) Inter-CPU locking barrier effects. + + - Locks vs memory accesses. + - Locks vs I/O accesses. + + (*) Where are memory barriers needed? + + - Interprocessor interaction. + - Atomic operations. + - Accessing devices. + - Interrupts. + + (*) Kernel I/O barrier effects. + + (*) Assumed minimum execution ordering model. + + (*) The effects of the cpu cache. + + - Cache coherency. + - Cache coherency vs DMA. + - Cache coherency vs MMIO. + + (*) The things CPUs get up to. + + - And then there's the Alpha. + + (*) Example uses. + + - Circular buffers. + + (*) References. + + +============================ +ABSTRACT MEMORY ACCESS MODEL +============================ + +Consider the following abstract model of the system: + + : : + : : + : : + +-------+ : +--------+ : +-------+ + | | : | | : | | + | | : | | : | | + | CPU 1 |<----->| Memory |<----->| CPU 2 | + | | : | | : | | + | | : | | : | | + +-------+ : +--------+ : +-------+ + ^ : ^ : ^ + | : | : | + | : | : | + | : v : | + | : +--------+ : | + | : | | : | + | : | | : | + +---------->| Device |<----------+ + : | | : + : | | : + : +--------+ : + : : + +Each CPU executes a program that generates memory access operations. In the +abstract CPU, memory operation ordering is very relaxed, and a CPU may actually +perform the memory operations in any order it likes, provided program causality +appears to be maintained. Similarly, the compiler may also arrange the +instructions it emits in any order it likes, provided it doesn't affect the +apparent operation of the program. + +So in the above diagram, the effects of the memory operations performed by a +CPU are perceived by the rest of the system as the operations cross the +interface between the CPU and rest of the system (the dotted lines). + + +For example, consider the following sequence of events: + + CPU 1 CPU 2 + =============== =============== + { A == 1; B == 2 } + A = 3; x = B; + B = 4; y = A; + +The set of accesses as seen by the memory system in the middle can be arranged +in 24 different combinations: + + STORE A=3, STORE B=4, y=LOAD A->3, x=LOAD B->4 + STORE A=3, STORE B=4, x=LOAD B->4, y=LOAD A->3 + STORE A=3, y=LOAD A->3, STORE B=4, x=LOAD B->4 + STORE A=3, y=LOAD A->3, x=LOAD B->2, STORE B=4 + STORE A=3, x=LOAD B->2, STORE B=4, y=LOAD A->3 + STORE A=3, x=LOAD B->2, y=LOAD A->3, STORE B=4 + STORE B=4, STORE A=3, y=LOAD A->3, x=LOAD B->4 + STORE B=4, ... + ... + +and can thus result in four different combinations of values: + + x == 2, y == 1 + x == 2, y == 3 + x == 4, y == 1 + x == 4, y == 3 + + +Furthermore, the stores committed by a CPU to the memory system may not be +perceived by the loads made by another CPU in the same order as the stores were +committed. + + +As a further example, consider this sequence of events: + + CPU 1 CPU 2 + =============== =============== + { A == 1, B == 2, C = 3, P == &A, Q == &C } + B = 4; Q = P; + P = &B D = *Q; + +There is an obvious data dependency here, as the value loaded into D depends on +the address retrieved from P by CPU 2. At the end of the sequence, any of the +following results are possible: + + (Q == &A) and (D == 1) + (Q == &B) and (D == 2) + (Q == &B) and (D == 4) + +Note that CPU 2 will never try and load C into D because the CPU will load P +into Q before issuing the load of *Q. + + +DEVICE OPERATIONS +----------------- + +Some devices present their control interfaces as collections of memory +locations, but the order in which the control registers are accessed is very +important. For instance, imagine an ethernet card with a set of internal +registers that are accessed through an address port register (A) and a data +port register (D). To read internal register 5, the following code might then +be used: + + *A = 5; + x = *D; + +but this might show up as either of the following two sequences: + + STORE *A = 5, x = LOAD *D + x = LOAD *D, STORE *A = 5 + +the second of which will almost certainly result in a malfunction, since it set +the address _after_ attempting to read the register. + + +GUARANTEES +---------- + +There are some minimal guarantees that may be expected of a CPU: + + (*) On any given CPU, dependent memory accesses will be issued in order, with + respect to itself. This means that for: + + ACCESS_ONCE(Q) = P; smp_read_barrier_depends(); D = ACCESS_ONCE(*Q); + + the CPU will issue the following memory operations: + + Q = LOAD P, D = LOAD *Q + + and always in that order. On most systems, smp_read_barrier_depends() + does nothing, but it is required for DEC Alpha. The ACCESS_ONCE() + is required to prevent compiler mischief. Please note that you + should normally use something like rcu_dereference() instead of + open-coding smp_read_barrier_depends(). + + (*) Overlapping loads and stores within a particular CPU will appear to be + ordered within that CPU. This means that for: + + a = ACCESS_ONCE(*X); ACCESS_ONCE(*X) = b; + + the CPU will only issue the following sequence of memory operations: + + a = LOAD *X, STORE *X = b + + And for: + + ACCESS_ONCE(*X) = c; d = ACCESS_ONCE(*X); + + the CPU will only issue: + + STORE *X = c, d = LOAD *X + + (Loads and stores overlap if they are targeted at overlapping pieces of + memory). + +And there are a number of things that _must_ or _must_not_ be assumed: + + (*) It _must_not_ be assumed that the compiler will do what you want with + memory references that are not protected by ACCESS_ONCE(). Without + ACCESS_ONCE(), the compiler is within its rights to do all sorts + of "creative" transformations, which are covered in the Compiler + Barrier section. + + (*) It _must_not_ be assumed that independent loads and stores will be issued + in the order given. This means that for: + + X = *A; Y = *B; *D = Z; + + we may get any of the following sequences: + + X = LOAD *A, Y = LOAD *B, STORE *D = Z + X = LOAD *A, STORE *D = Z, Y = LOAD *B + Y = LOAD *B, X = LOAD *A, STORE *D = Z + Y = LOAD *B, STORE *D = Z, X = LOAD *A + STORE *D = Z, X = LOAD *A, Y = LOAD *B + STORE *D = Z, Y = LOAD *B, X = LOAD *A + + (*) It _must_ be assumed that overlapping memory accesses may be merged or + discarded. This means that for: + + X = *A; Y = *(A + 4); + + we may get any one of the following sequences: + + X = LOAD *A; Y = LOAD *(A + 4); + Y = LOAD *(A + 4); X = LOAD *A; + {X, Y} = LOAD {*A, *(A + 4) }; + + And for: + + *A = X; *(A + 4) = Y; + + we may get any of: + + STORE *A = X; STORE *(A + 4) = Y; + STORE *(A + 4) = Y; STORE *A = X; + STORE {*A, *(A + 4) } = {X, Y}; + +And there are anti-guarantees: + + (*) These guarantees do not apply to bitfields, because compilers often + generate code to modify these using non-atomic read-modify-write + sequences. Do not attempt to use bitfields to synchronize parallel + algorithms. + + (*) Even in cases where bitfields are protected by locks, all fields + in a given bitfield must be protected by one lock. If two fields + in a given bitfield are protected by different locks, the compiler's + non-atomic read-modify-write sequences can cause an update to one + field to corrupt the value of an adjacent field. + + (*) These guarantees apply only to properly aligned and sized scalar + variables. "Properly sized" currently means variables that are + the same size as "char", "short", "int" and "long". "Properly + aligned" means the natural alignment, thus no constraints for + "char", two-byte alignment for "short", four-byte alignment for + "int", and either four-byte or eight-byte alignment for "long", + on 32-bit and 64-bit systems, respectively. Note that these + guarantees were introduced into the C11 standard, so beware when + using older pre-C11 compilers (for example, gcc 4.6). The portion + of the standard containing this guarantee is Section 3.14, which + defines "memory location" as follows: + + memory location + either an object of scalar type, or a maximal sequence + of adjacent bit-fields all having nonzero width + + NOTE 1: Two threads of execution can update and access + separate memory locations without interfering with + each other. + + NOTE 2: A bit-field and an adjacent non-bit-field member + are in separate memory locations. The same applies + to two bit-fields, if one is declared inside a nested + structure declaration and the other is not, or if the two + are separated by a zero-length bit-field declaration, + or if they are separated by a non-bit-field member + declaration. It is not safe to concurrently update two + bit-fields in the same structure if all members declared + between them are also bit-fields, no matter what the + sizes of those intervening bit-fields happen to be. + + +========================= +WHAT ARE MEMORY BARRIERS? +========================= + +As can be seen above, independent memory operations are effectively performed +in random order, but this can be a problem for CPU-CPU interaction and for I/O. +What is required is some way of intervening to instruct the compiler and the +CPU to restrict the order. + +Memory barriers are such interventions. They impose a perceived partial +ordering over the memory operations on either side of the barrier. + +Such enforcement is important because the CPUs and other devices in a system +can use a variety of tricks to improve performance, including reordering, +deferral and combination of memory operations; speculative loads; speculative +branch prediction and various types of caching. Memory barriers are used to +override or suppress these tricks, allowing the code to sanely control the +interaction of multiple CPUs and/or devices. + + +VARIETIES OF MEMORY BARRIER +--------------------------- + +Memory barriers come in four basic varieties: + + (1) Write (or store) memory barriers. + + A write memory barrier gives a guarantee that all the STORE operations + specified before the barrier will appear to happen before all the STORE + operations specified after the barrier with respect to the other + components of the system. + + A write barrier is a partial ordering on stores only; it is not required + to have any effect on loads. + + A CPU can be viewed as committing a sequence of store operations to the + memory system as time progresses. All stores before a write barrier will + occur in the sequence _before_ all the stores after the write barrier. + + [!] Note that write barriers should normally be paired with read or data + dependency barriers; see the "SMP barrier pairing" subsection. + + + (2) Data dependency barriers. + + A data dependency barrier is a weaker form of read barrier. In the case + where two loads are performed such that the second depends on the result + of the first (eg: the first load retrieves the address to which the second + load will be directed), a data dependency barrier would be required to + make sure that the target of the second load is updated before the address + obtained by the first load is accessed. + + A data dependency barrier is a partial ordering on interdependent loads + only; it is not required to have any effect on stores, independent loads + or overlapping loads. + + As mentioned in (1), the other CPUs in the system can be viewed as + committing sequences of stores to the memory system that the CPU being + considered can then perceive. A data dependency barrier issued by the CPU + under consideration guarantees that for any load preceding it, if that + load touches one of a sequence of stores from another CPU, then by the + time the barrier completes, the effects of all the stores prior to that + touched by the load will be perceptible to any loads issued after the data + dependency barrier. + + See the "Examples of memory barrier sequences" subsection for diagrams + showing the ordering constraints. + + [!] Note that the first load really has to have a _data_ dependency and + not a control dependency. If the address for the second load is dependent + on the first load, but the dependency is through a conditional rather than + actually loading the address itself, then it's a _control_ dependency and + a full read barrier or better is required. See the "Control dependencies" + subsection for more information. + + [!] Note that data dependency barriers should normally be paired with + write barriers; see the "SMP barrier pairing" subsection. + + + (3) Read (or load) memory barriers. + + A read barrier is a data dependency barrier plus a guarantee that all the + LOAD operations specified before the barrier will appear to happen before + all the LOAD operations specified after the barrier with respect to the + other components of the system. + + A read barrier is a partial ordering on loads only; it is not required to + have any effect on stores. + + Read memory barriers imply data dependency barriers, and so can substitute + for them. + + [!] Note that read barriers should normally be paired with write barriers; + see the "SMP barrier pairing" subsection. + + + (4) General memory barriers. + + A general memory barrier gives a guarantee that all the LOAD and STORE + operations specified before the barrier will appear to happen before all + the LOAD and STORE operations specified after the barrier with respect to + the other components of the system. + + A general memory barrier is a partial ordering over both loads and stores. + + General memory barriers imply both read and write memory barriers, and so + can substitute for either. + + +And a couple of implicit varieties: + + (5) ACQUIRE operations. + + This acts as a one-way permeable barrier. It guarantees that all memory + operations after the ACQUIRE operation will appear to happen after the + ACQUIRE operation with respect to the other components of the system. + ACQUIRE operations include LOCK operations and smp_load_acquire() + operations. + + Memory operations that occur before an ACQUIRE operation may appear to + happen after it completes. + + An ACQUIRE operation should almost always be paired with a RELEASE + operation. + + + (6) RELEASE operations. + + This also acts as a one-way permeable barrier. It guarantees that all + memory operations before the RELEASE operation will appear to happen + before the RELEASE operation with respect to the other components of the + system. RELEASE operations include UNLOCK operations and + smp_store_release() operations. + + Memory operations that occur after a RELEASE operation may appear to + happen before it completes. + + The use of ACQUIRE and RELEASE operations generally precludes the need + for other sorts of memory barrier (but note the exceptions mentioned in + the subsection "MMIO write barrier"). In addition, a RELEASE+ACQUIRE + pair is -not- guaranteed to act as a full memory barrier. However, after + an ACQUIRE on a given variable, all memory accesses preceding any prior + RELEASE on that same variable are guaranteed to be visible. In other + words, within a given variable's critical section, all accesses of all + previous critical sections for that variable are guaranteed to have + completed. + + This means that ACQUIRE acts as a minimal "acquire" operation and + RELEASE acts as a minimal "release" operation. + + +Memory barriers are only required where there's a possibility of interaction +between two CPUs or between a CPU and a device. If it can be guaranteed that +there won't be any such interaction in any particular piece of code, then +memory barriers are unnecessary in that piece of code. + + +Note that these are the _minimum_ guarantees. Different architectures may give +more substantial guarantees, but they may _not_ be relied upon outside of arch +specific code. + + +WHAT MAY NOT BE ASSUMED ABOUT MEMORY BARRIERS? +---------------------------------------------- + +There are certain things that the Linux kernel memory barriers do not guarantee: + + (*) There is no guarantee that any of the memory accesses specified before a + memory barrier will be _complete_ by the completion of a memory barrier + instruction; the barrier can be considered to draw a line in that CPU's + access queue that accesses of the appropriate type may not cross. + + (*) There is no guarantee that issuing a memory barrier on one CPU will have + any direct effect on another CPU or any other hardware in the system. The + indirect effect will be the order in which the second CPU sees the effects + of the first CPU's accesses occur, but see the next point: + + (*) There is no guarantee that a CPU will see the correct order of effects + from a second CPU's accesses, even _if_ the second CPU uses a memory + barrier, unless the first CPU _also_ uses a matching memory barrier (see + the subsection on "SMP Barrier Pairing"). + + (*) There is no guarantee that some intervening piece of off-the-CPU + hardware[*] will not reorder the memory accesses. CPU cache coherency + mechanisms should propagate the indirect effects of a memory barrier + between CPUs, but might not do so in order. + + [*] For information on bus mastering DMA and coherency please read: + + Documentation/PCI/pci.txt + Documentation/DMA-API-HOWTO.txt + Documentation/DMA-API.txt + + +DATA DEPENDENCY BARRIERS +------------------------ + +The usage requirements of data dependency barriers are a little subtle, and +it's not always obvious that they're needed. To illustrate, consider the +following sequence of events: + + CPU 1 CPU 2 + =============== =============== + { A == 1, B == 2, C = 3, P == &A, Q == &C } + B = 4; + <write barrier> + ACCESS_ONCE(P) = &B + Q = ACCESS_ONCE(P); + D = *Q; + +There's a clear data dependency here, and it would seem that by the end of the +sequence, Q must be either &A or &B, and that: + + (Q == &A) implies (D == 1) + (Q == &B) implies (D == 4) + +But! CPU 2's perception of P may be updated _before_ its perception of B, thus +leading to the following situation: + + (Q == &B) and (D == 2) ???? + +Whilst this may seem like a failure of coherency or causality maintenance, it +isn't, and this behaviour can be observed on certain real CPUs (such as the DEC +Alpha). + +To deal with this, a data dependency barrier or better must be inserted +between the address load and the data load: + + CPU 1 CPU 2 + =============== =============== + { A == 1, B == 2, C = 3, P == &A, Q == &C } + B = 4; + <write barrier> + ACCESS_ONCE(P) = &B + Q = ACCESS_ONCE(P); + <data dependency barrier> + D = *Q; + +This enforces the occurrence of one of the two implications, and prevents the +third possibility from arising. + +[!] Note that this extremely counterintuitive situation arises most easily on +machines with split caches, so that, for example, one cache bank processes +even-numbered cache lines and the other bank processes odd-numbered cache +lines. The pointer P might be stored in an odd-numbered cache line, and the +variable B might be stored in an even-numbered cache line. Then, if the +even-numbered bank of the reading CPU's cache is extremely busy while the +odd-numbered bank is idle, one can see the new value of the pointer P (&B), +but the old value of the variable B (2). + + +Another example of where data dependency barriers might be required is where a +number is read from memory and then used to calculate the index for an array +access: + + CPU 1 CPU 2 + =============== =============== + { M[0] == 1, M[1] == 2, M[3] = 3, P == 0, Q == 3 } + M[1] = 4; + <write barrier> + ACCESS_ONCE(P) = 1 + Q = ACCESS_ONCE(P); + <data dependency barrier> + D = M[Q]; + + +The data dependency barrier is very important to the RCU system, +for example. See rcu_assign_pointer() and rcu_dereference() in +include/linux/rcupdate.h. This permits the current target of an RCU'd +pointer to be replaced with a new modified target, without the replacement +target appearing to be incompletely initialised. + +See also the subsection on "Cache Coherency" for a more thorough example. + + +CONTROL DEPENDENCIES +-------------------- + +A load-load control dependency requires a full read memory barrier, not +simply a data dependency barrier to make it work correctly. Consider the +following bit of code: + + q = ACCESS_ONCE(a); + if (q) { + <data dependency barrier> /* BUG: No data dependency!!! */ + p = ACCESS_ONCE(b); + } + +This will not have the desired effect because there is no actual data +dependency, but rather a control dependency that the CPU may short-circuit +by attempting to predict the outcome in advance, so that other CPUs see +the load from b as having happened before the load from a. In such a +case what's actually required is: + + q = ACCESS_ONCE(a); + if (q) { + <read barrier> + p = ACCESS_ONCE(b); + } + +However, stores are not speculated. This means that ordering -is- provided +for load-store control dependencies, as in the following example: + + q = ACCESS_ONCE(a); + if (q) { + ACCESS_ONCE(b) = p; + } + +Control dependencies pair normally with other types of barriers. +That said, please note that ACCESS_ONCE() is not optional! Without the +ACCESS_ONCE(), might combine the load from 'a' with other loads from +'a', and the store to 'b' with other stores to 'b', with possible highly +counterintuitive effects on ordering. + +Worse yet, if the compiler is able to prove (say) that the value of +variable 'a' is always non-zero, it would be well within its rights +to optimize the original example by eliminating the "if" statement +as follows: + + q = a; + b = p; /* BUG: Compiler and CPU can both reorder!!! */ + +So don't leave out the ACCESS_ONCE(). + +It is tempting to try to enforce ordering on identical stores on both +branches of the "if" statement as follows: + + q = ACCESS_ONCE(a); + if (q) { + barrier(); + ACCESS_ONCE(b) = p; + do_something(); + } else { + barrier(); + ACCESS_ONCE(b) = p; + do_something_else(); + } + +Unfortunately, current compilers will transform this as follows at high +optimization levels: + + q = ACCESS_ONCE(a); + barrier(); + ACCESS_ONCE(b) = p; /* BUG: No ordering vs. load from a!!! */ + if (q) { + /* ACCESS_ONCE(b) = p; -- moved up, BUG!!! */ + do_something(); + } else { + /* ACCESS_ONCE(b) = p; -- moved up, BUG!!! */ + do_something_else(); + } + +Now there is no conditional between the load from 'a' and the store to +'b', which means that the CPU is within its rights to reorder them: +The conditional is absolutely required, and must be present in the +assembly code even after all compiler optimizations have been applied. +Therefore, if you need ordering in this example, you need explicit +memory barriers, for example, smp_store_release(): + + q = ACCESS_ONCE(a); + if (q) { + smp_store_release(&b, p); + do_something(); + } else { + smp_store_release(&b, p); + do_something_else(); + } + +In contrast, without explicit memory barriers, two-legged-if control +ordering is guaranteed only when the stores differ, for example: + + q = ACCESS_ONCE(a); + if (q) { + ACCESS_ONCE(b) = p; + do_something(); + } else { + ACCESS_ONCE(b) = r; + do_something_else(); + } + +The initial ACCESS_ONCE() is still required to prevent the compiler from +proving the value of 'a'. + +In addition, you need to be careful what you do with the local variable 'q', +otherwise the compiler might be able to guess the value and again remove +the needed conditional. For example: + + q = ACCESS_ONCE(a); + if (q % MAX) { + ACCESS_ONCE(b) = p; + do_something(); + } else { + ACCESS_ONCE(b) = r; + do_something_else(); + } + +If MAX is defined to be 1, then the compiler knows that (q % MAX) is +equal to zero, in which case the compiler is within its rights to +transform the above code into the following: + + q = ACCESS_ONCE(a); + ACCESS_ONCE(b) = p; + do_something_else(); + +Given this transformation, the CPU is not required to respect the ordering +between the load from variable 'a' and the store to variable 'b'. It is +tempting to add a barrier(), but this does not help. The conditional +is gone, and the barrier won't bring it back. Therefore, if you are +relying on this ordering, you should make sure that MAX is greater than +one, perhaps as follows: + + q = ACCESS_ONCE(a); + BUILD_BUG_ON(MAX <= 1); /* Order load from a with store to b. */ + if (q % MAX) { + ACCESS_ONCE(b) = p; + do_something(); + } else { + ACCESS_ONCE(b) = r; + do_something_else(); + } + +Please note once again that the stores to 'b' differ. If they were +identical, as noted earlier, the compiler could pull this store outside +of the 'if' statement. + +You must also be careful not to rely too much on boolean short-circuit +evaluation. Consider this example: + + q = ACCESS_ONCE(a); + if (a || 1 > 0) + ACCESS_ONCE(b) = 1; + +Because the second condition is always true, the compiler can transform +this example as following, defeating control dependency: + + q = ACCESS_ONCE(a); + ACCESS_ONCE(b) = 1; + +This example underscores the need to ensure that the compiler cannot +out-guess your code. More generally, although ACCESS_ONCE() does force +the compiler to actually emit code for a given load, it does not force +the compiler to use the results. + +Finally, control dependencies do -not- provide transitivity. This is +demonstrated by two related examples, with the initial values of +x and y both being zero: + + CPU 0 CPU 1 + ===================== ===================== + r1 = ACCESS_ONCE(x); r2 = ACCESS_ONCE(y); + if (r1 > 0) if (r2 > 0) + ACCESS_ONCE(y) = 1; ACCESS_ONCE(x) = 1; + + assert(!(r1 == 1 && r2 == 1)); + +The above two-CPU example will never trigger the assert(). However, +if control dependencies guaranteed transitivity (which they do not), +then adding the following CPU would guarantee a related assertion: + + CPU 2 + ===================== + ACCESS_ONCE(x) = 2; + + assert(!(r1 == 2 && r2 == 1 && x == 2)); /* FAILS!!! */ + +But because control dependencies do -not- provide transitivity, the above +assertion can fail after the combined three-CPU example completes. If you +need the three-CPU example to provide ordering, you will need smp_mb() +between the loads and stores in the CPU 0 and CPU 1 code fragments, +that is, just before or just after the "if" statements. + +These two examples are the LB and WWC litmus tests from this paper: +http://www.cl.cam.ac.uk/users/pes20/ppc-supplemental/test6.pdf and this +site: https://www.cl.cam.ac.uk/~pes20/ppcmem/index.html. + +In summary: + + (*) Control dependencies can order prior loads against later stores. + However, they do -not- guarantee any other sort of ordering: + Not prior loads against later loads, nor prior stores against + later anything. If you need these other forms of ordering, + use smp_rmb(), smp_wmb(), or, in the case of prior stores and + later loads, smp_mb(). + + (*) If both legs of the "if" statement begin with identical stores + to the same variable, a barrier() statement is required at the + beginning of each leg of the "if" statement. + + (*) Control dependencies require at least one run-time conditional + between the prior load and the subsequent store, and this + conditional must involve the prior load. If the compiler + is able to optimize the conditional away, it will have also + optimized away the ordering. Careful use of ACCESS_ONCE() can + help to preserve the needed conditional. + + (*) Control dependencies require that the compiler avoid reordering the + dependency into nonexistence. Careful use of ACCESS_ONCE() or + barrier() can help to preserve your control dependency. Please + see the Compiler Barrier section for more information. + + (*) Control dependencies pair normally with other types of barriers. + + (*) Control dependencies do -not- provide transitivity. If you + need transitivity, use smp_mb(). + + +SMP BARRIER PAIRING +------------------- + +When dealing with CPU-CPU interactions, certain types of memory barrier should +always be paired. A lack of appropriate pairing is almost certainly an error. + +General barriers pair with each other, though they also pair with most +other types of barriers, albeit without transitivity. An acquire barrier +pairs with a release barrier, but both may also pair with other barriers, +including of course general barriers. A write barrier pairs with a data +dependency barrier, a control dependency, an acquire barrier, a release +barrier, a read barrier, or a general barrier. Similarly a read barrier, +control dependency, or a data dependency barrier pairs with a write +barrier, an acquire barrier, a release barrier, or a general barrier: + + CPU 1 CPU 2 + =============== =============== + ACCESS_ONCE(a) = 1; + <write barrier> + ACCESS_ONCE(b) = 2; x = ACCESS_ONCE(b); + <read barrier> + y = ACCESS_ONCE(a); + +Or: + + CPU 1 CPU 2 + =============== =============================== + a = 1; + <write barrier> + ACCESS_ONCE(b) = &a; x = ACCESS_ONCE(b); + <data dependency barrier> + y = *x; + +Or even: + + CPU 1 CPU 2 + =============== =============================== + r1 = ACCESS_ONCE(y); + <general barrier> + ACCESS_ONCE(y) = 1; if (r2 = ACCESS_ONCE(x)) { + <implicit control dependency> + ACCESS_ONCE(y) = 1; + } + + assert(r1 == 0 || r2 == 0); + +Basically, the read barrier always has to be there, even though it can be of +the "weaker" type. + +[!] Note that the stores before the write barrier would normally be expected to +match the loads after the read barrier or the data dependency barrier, and vice +versa: + + CPU 1 CPU 2 + =================== =================== + ACCESS_ONCE(a) = 1; }---- --->{ v = ACCESS_ONCE(c); + ACCESS_ONCE(b) = 2; } \ / { w = ACCESS_ONCE(d); + <write barrier> \ <read barrier> + ACCESS_ONCE(c) = 3; } / \ { x = ACCESS_ONCE(a); + ACCESS_ONCE(d) = 4; }---- --->{ y = ACCESS_ONCE(b); + + +EXAMPLES OF MEMORY BARRIER SEQUENCES +------------------------------------ + +Firstly, write barriers act as partial orderings on store operations. +Consider the following sequence of events: + + CPU 1 + ======================= + STORE A = 1 + STORE B = 2 + STORE C = 3 + <write barrier> + STORE D = 4 + STORE E = 5 + +This sequence of events is committed to the memory coherence system in an order +that the rest of the system might perceive as the unordered set of { STORE A, +STORE B, STORE C } all occurring before the unordered set of { STORE D, STORE E +}: + + +-------+ : : + | | +------+ + | |------>| C=3 | } /\ + | | : +------+ }----- \ -----> Events perceptible to + | | : | A=1 | } \/ the rest of the system + | | : +------+ } + | CPU 1 | : | B=2 | } + | | +------+ } + | | wwwwwwwwwwwwwwww } <--- At this point the write barrier + | | +------+ } requires all stores prior to the + | | : | E=5 | } barrier to be committed before + | | : +------+ } further stores may take place + | |------>| D=4 | } + | | +------+ + +-------+ : : + | + | Sequence in which stores are committed to the + | memory system by CPU 1 + V + + +Secondly, data dependency barriers act as partial orderings on data-dependent +loads. Consider the following sequence of events: + + CPU 1 CPU 2 + ======================= ======================= + { B = 7; X = 9; Y = 8; C = &Y } + STORE A = 1 + STORE B = 2 + <write barrier> + STORE C = &B LOAD X + STORE D = 4 LOAD C (gets &B) + LOAD *C (reads B) + +Without intervention, CPU 2 may perceive the events on CPU 1 in some +effectively random order, despite the write barrier issued by CPU 1: + + +-------+ : : : : + | | +------+ +-------+ | Sequence of update + | |------>| B=2 |----- --->| Y->8 | | of perception on + | | : +------+ \ +-------+ | CPU 2 + | CPU 1 | : | A=1 | \ --->| C->&Y | V + | | +------+ | +-------+ + | | wwwwwwwwwwwwwwww | : : + | | +------+ | : : + | | : | C=&B |--- | : : +-------+ + | | : +------+ \ | +-------+ | | + | |------>| D=4 | ----------->| C->&B |------>| | + | | +------+ | +-------+ | | + +-------+ : : | : : | | + | : : | | + | : : | CPU 2 | + | +-------+ | | + Apparently incorrect ---> | | B->7 |------>| | + perception of B (!) | +-------+ | | + | : : | | + | +-------+ | | + The load of X holds ---> \ | X->9 |------>| | + up the maintenance \ +-------+ | | + of coherence of B ----->| B->2 | +-------+ + +-------+ + : : + + +In the above example, CPU 2 perceives that B is 7, despite the load of *C +(which would be B) coming after the LOAD of C. + +If, however, a data dependency barrier were to be placed between the load of C +and the load of *C (ie: B) on CPU 2: + + CPU 1 CPU 2 + ======================= ======================= + { B = 7; X = 9; Y = 8; C = &Y } + STORE A = 1 + STORE B = 2 + <write barrier> + STORE C = &B LOAD X + STORE D = 4 LOAD C (gets &B) + <data dependency barrier> + LOAD *C (reads B) + +then the following will occur: + + +-------+ : : : : + | | +------+ +-------+ + | |------>| B=2 |----- --->| Y->8 | + | | : +------+ \ +-------+ + | CPU 1 | : | A=1 | \ --->| C->&Y | + | | +------+ | +-------+ + | | wwwwwwwwwwwwwwww | : : + | | +------+ | : : + | | : | C=&B |--- | : : +-------+ + | | : +------+ \ | +-------+ | | + | |------>| D=4 | ----------->| C->&B |------>| | + | | +------+ | +-------+ | | + +-------+ : : | : : | | + | : : | | + | : : | CPU 2 | + | +-------+ | | + | | X->9 |------>| | + | +-------+ | | + Makes sure all effects ---> \ ddddddddddddddddd | | + prior to the store of C \ +-------+ | | + are perceptible to ----->| B->2 |------>| | + subsequent loads +-------+ | | + : : +-------+ + + +And thirdly, a read barrier acts as a partial order on loads. Consider the +following sequence of events: + + CPU 1 CPU 2 + ======================= ======================= + { A = 0, B = 9 } + STORE A=1 + <write barrier> + STORE B=2 + LOAD B + LOAD A + +Without intervention, CPU 2 may then choose to perceive the events on CPU 1 in +some effectively random order, despite the write barrier issued by CPU 1: + + +-------+ : : : : + | | +------+ +-------+ + | |------>| A=1 |------ --->| A->0 | + | | +------+ \ +-------+ + | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 | + | | +------+ | +-------+ + | |------>| B=2 |--- | : : + | | +------+ \ | : : +-------+ + +-------+ : : \ | +-------+ | | + ---------->| B->2 |------>| | + | +-------+ | CPU 2 | + | | A->0 |------>| | + | +-------+ | | + | : : +-------+ + \ : : + \ +-------+ + ---->| A->1 | + +-------+ + : : + + +If, however, a read barrier were to be placed between the load of B and the +load of A on CPU 2: + + CPU 1 CPU 2 + ======================= ======================= + { A = 0, B = 9 } + STORE A=1 + <write barrier> + STORE B=2 + LOAD B + <read barrier> + LOAD A + +then the partial ordering imposed by CPU 1 will be perceived correctly by CPU +2: + + +-------+ : : : : + | | +------+ +-------+ + | |------>| A=1 |------ --->| A->0 | + | | +------+ \ +-------+ + | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 | + | | +------+ | +-------+ + | |------>| B=2 |--- | : : + | | +------+ \ | : : +-------+ + +-------+ : : \ | +-------+ | | + ---------->| B->2 |------>| | + | +-------+ | CPU 2 | + | : : | | + | : : | | + At this point the read ----> \ rrrrrrrrrrrrrrrrr | | + barrier causes all effects \ +-------+ | | + prior to the storage of B ---->| A->1 |------>| | + to be perceptible to CPU 2 +-------+ | | + : : +-------+ + + +To illustrate this more completely, consider what could happen if the code +contained a load of A either side of the read barrier: + + CPU 1 CPU 2 + ======================= ======================= + { A = 0, B = 9 } + STORE A=1 + <write barrier> + STORE B=2 + LOAD B + LOAD A [first load of A] + <read barrier> + LOAD A [second load of A] + +Even though the two loads of A both occur after the load of B, they may both +come up with different values: + + +-------+ : : : : + | | +------+ +-------+ + | |------>| A=1 |------ --->| A->0 | + | | +------+ \ +-------+ + | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 | + | | +------+ | +-------+ + | |------>| B=2 |--- | : : + | | +------+ \ | : : +-------+ + +-------+ : : \ | +-------+ | | + ---------->| B->2 |------>| | + | +-------+ | CPU 2 | + | : : | | + | : : | | + | +-------+ | | + | | A->0 |------>| 1st | + | +-------+ | | + At this point the read ----> \ rrrrrrrrrrrrrrrrr | | + barrier causes all effects \ +-------+ | | + prior to the storage of B ---->| A->1 |------>| 2nd | + to be perceptible to CPU 2 +-------+ | | + : : +-------+ + + +But it may be that the update to A from CPU 1 becomes perceptible to CPU 2 +before the read barrier completes anyway: + + +-------+ : : : : + | | +------+ +-------+ + | |------>| A=1 |------ --->| A->0 | + | | +------+ \ +-------+ + | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 | + | | +------+ | +-------+ + | |------>| B=2 |--- | : : + | | +------+ \ | : : +-------+ + +-------+ : : \ | +-------+ | | + ---------->| B->2 |------>| | + | +-------+ | CPU 2 | + | : : | | + \ : : | | + \ +-------+ | | + ---->| A->1 |------>| 1st | + +-------+ | | + rrrrrrrrrrrrrrrrr | | + +-------+ | | + | A->1 |------>| 2nd | + +-------+ | | + : : +-------+ + + +The guarantee is that the second load will always come up with A == 1 if the +load of B came up with B == 2. No such guarantee exists for the first load of +A; that may come up with either A == 0 or A == 1. + + +READ MEMORY BARRIERS VS LOAD SPECULATION +---------------------------------------- + +Many CPUs speculate with loads: that is they see that they will need to load an +item from memory, and they find a time where they're not using the bus for any +other loads, and so do the load in advance - even though they haven't actually +got to that point in the instruction execution flow yet. This permits the +actual load instruction to potentially complete immediately because the CPU +already has the value to hand. + +It may turn out that the CPU didn't actually need the value - perhaps because a +branch circumvented the load - in which case it can discard the value or just +cache it for later use. + +Consider: + + CPU 1 CPU 2 + ======================= ======================= + LOAD B + DIVIDE } Divide instructions generally + DIVIDE } take a long time to perform + LOAD A + +Which might appear as this: + + : : +-------+ + +-------+ | | + --->| B->2 |------>| | + +-------+ | CPU 2 | + : :DIVIDE | | + +-------+ | | + The CPU being busy doing a ---> --->| A->0 |~~~~ | | + division speculates on the +-------+ ~ | | + LOAD of A : : ~ | | + : :DIVIDE | | + : : ~ | | + Once the divisions are complete --> : : ~-->| | + the CPU can then perform the : : | | + LOAD with immediate effect : : +-------+ + + +Placing a read barrier or a data dependency barrier just before the second +load: + + CPU 1 CPU 2 + ======================= ======================= + LOAD B + DIVIDE + DIVIDE + <read barrier> + LOAD A + +will force any value speculatively obtained to be reconsidered to an extent +dependent on the type of barrier used. If there was no change made to the +speculated memory location, then the speculated value will just be used: + + : : +-------+ + +-------+ | | + --->| B->2 |------>| | + +-------+ | CPU 2 | + : :DIVIDE | | + +-------+ | | + The CPU being busy doing a ---> --->| A->0 |~~~~ | | + division speculates on the +-------+ ~ | | + LOAD of A : : ~ | | + : :DIVIDE | | + : : ~ | | + : : ~ | | + rrrrrrrrrrrrrrrr~ | | + : : ~ | | + : : ~-->| | + : : | | + : : +-------+ + + +but if there was an update or an invalidation from another CPU pending, then +the speculation will be cancelled and the value reloaded: + + : : +-------+ + +-------+ | | + --->| B->2 |------>| | + +-------+ | CPU 2 | + : :DIVIDE | | + +-------+ | | + The CPU being busy doing a ---> --->| A->0 |~~~~ | | + division speculates on the +-------+ ~ | | + LOAD of A : : ~ | | + : :DIVIDE | | + : : ~ | | + : : ~ | | + rrrrrrrrrrrrrrrrr | | + +-------+ | | + The speculation is discarded ---> --->| A->1 |------>| | + and an updated value is +-------+ | | + retrieved : : +-------+ + + +TRANSITIVITY +------------ + +Transitivity is a deeply intuitive notion about ordering that is not +always provided by real computer systems. The following example +demonstrates transitivity (also called "cumulativity"): + + CPU 1 CPU 2 CPU 3 + ======================= ======================= ======================= + { X = 0, Y = 0 } + STORE X=1 LOAD X STORE Y=1 + <general barrier> <general barrier> + LOAD Y LOAD X + +Suppose that CPU 2's load from X returns 1 and its load from Y returns 0. +This indicates that CPU 2's load from X in some sense follows CPU 1's +store to X and that CPU 2's load from Y in some sense preceded CPU 3's +store to Y. The question is then "Can CPU 3's load from X return 0?" + +Because CPU 2's load from X in some sense came after CPU 1's store, it +is natural to expect that CPU 3's load from X must therefore return 1. +This expectation is an example of transitivity: if a load executing on +CPU A follows a load from the same variable executing on CPU B, then +CPU A's load must either return the same value that CPU B's load did, +or must return some later value. + +In the Linux kernel, use of general memory barriers guarantees +transitivity. Therefore, in the above example, if CPU 2's load from X +returns 1 and its load from Y returns 0, then CPU 3's load from X must +also return 1. + +However, transitivity is -not- guaranteed for read or write barriers. +For example, suppose that CPU 2's general barrier in the above example +is changed to a read barrier as shown below: + + CPU 1 CPU 2 CPU 3 + ======================= ======================= ======================= + { X = 0, Y = 0 } + STORE X=1 LOAD X STORE Y=1 + <read barrier> <general barrier> + LOAD Y LOAD X + +This substitution destroys transitivity: in this example, it is perfectly +legal for CPU 2's load from X to return 1, its load from Y to return 0, +and CPU 3's load from X to return 0. + +The key point is that although CPU 2's read barrier orders its pair +of loads, it does not guarantee to order CPU 1's store. Therefore, if +this example runs on a system where CPUs 1 and 2 share a store buffer +or a level of cache, CPU 2 might have early access to CPU 1's writes. +General barriers are therefore required to ensure that all CPUs agree +on the combined order of CPU 1's and CPU 2's accesses. + +To reiterate, if your code requires transitivity, use general barriers +throughout. + + +======================== +EXPLICIT KERNEL BARRIERS +======================== + +The Linux kernel has a variety of different barriers that act at different +levels: + + (*) Compiler barrier. + + (*) CPU memory barriers. + + (*) MMIO write barrier. + + +COMPILER BARRIER +---------------- + +The Linux kernel has an explicit compiler barrier function that prevents the +compiler from moving the memory accesses either side of it to the other side: + + barrier(); + +This is a general barrier -- there are no read-read or write-write variants +of barrier(). However, ACCESS_ONCE() can be thought of as a weak form +for barrier() that affects only the specific accesses flagged by the +ACCESS_ONCE(). + +The barrier() function has the following effects: + + (*) Prevents the compiler from reordering accesses following the + barrier() to precede any accesses preceding the barrier(). + One example use for this property is to ease communication between + interrupt-handler code and the code that was interrupted. + + (*) Within a loop, forces the compiler to load the variables used + in that loop's conditional on each pass through that loop. + +The ACCESS_ONCE() function can prevent any number of optimizations that, +while perfectly safe in single-threaded code, can be fatal in concurrent +code. Here are some examples of these sorts of optimizations: + + (*) The compiler is within its rights to reorder loads and stores + to the same variable, and in some cases, the CPU is within its + rights to reorder loads to the same variable. This means that + the following code: + + a[0] = x; + a[1] = x; + + Might result in an older value of x stored in a[1] than in a[0]. + Prevent both the compiler and the CPU from doing this as follows: + + a[0] = ACCESS_ONCE(x); + a[1] = ACCESS_ONCE(x); + + In short, ACCESS_ONCE() provides cache coherence for accesses from + multiple CPUs to a single variable. + + (*) The compiler is within its rights to merge successive loads from + the same variable. Such merging can cause the compiler to "optimize" + the following code: + + while (tmp = a) + do_something_with(tmp); + + into the following code, which, although in some sense legitimate + for single-threaded code, is almost certainly not what the developer + intended: + + if (tmp = a) + for (;;) + do_something_with(tmp); + + Use ACCESS_ONCE() to prevent the compiler from doing this to you: + + while (tmp = ACCESS_ONCE(a)) + do_something_with(tmp); + + (*) The compiler is within its rights to reload a variable, for example, + in cases where high register pressure prevents the compiler from + keeping all data of interest in registers. The compiler might + therefore optimize the variable 'tmp' out of our previous example: + + while (tmp = a) + do_something_with(tmp); + + This could result in the following code, which is perfectly safe in + single-threaded code, but can be fatal in concurrent code: + + while (a) + do_something_with(a); + + For example, the optimized version of this code could result in + passing a zero to do_something_with() in the case where the variable + a was modified by some other CPU between the "while" statement and + the call to do_something_with(). + + Again, use ACCESS_ONCE() to prevent the compiler from doing this: + + while (tmp = ACCESS_ONCE(a)) + do_something_with(tmp); + + Note that if the compiler runs short of registers, it might save + tmp onto the stack. The overhead of this saving and later restoring + is why compilers reload variables. Doing so is perfectly safe for + single-threaded code, so you need to tell the compiler about cases + where it is not safe. + + (*) The compiler is within its rights to omit a load entirely if it knows + what the value will be. For example, if the compiler can prove that + the value of variable 'a' is always zero, it can optimize this code: + + while (tmp = a) + do_something_with(tmp); + + Into this: + + do { } while (0); + + This transformation is a win for single-threaded code because it gets + rid of a load and a branch. The problem is that the compiler will + carry out its proof assuming that the current CPU is the only one + updating variable 'a'. If variable 'a' is shared, then the compiler's + proof will be erroneous. Use ACCESS_ONCE() to tell the compiler + that it doesn't know as much as it thinks it does: + + while (tmp = ACCESS_ONCE(a)) + do_something_with(tmp); + + But please note that the compiler is also closely watching what you + do with the value after the ACCESS_ONCE(). For example, suppose you + do the following and MAX is a preprocessor macro with the value 1: + + while ((tmp = ACCESS_ONCE(a)) % MAX) + do_something_with(tmp); + + Then the compiler knows that the result of the "%" operator applied + to MAX will always be zero, again allowing the compiler to optimize + the code into near-nonexistence. (It will still load from the + variable 'a'.) + + (*) Similarly, the compiler is within its rights to omit a store entirely + if it knows that the variable already has the value being stored. + Again, the compiler assumes that the current CPU is the only one + storing into the variable, which can cause the compiler to do the + wrong thing for shared variables. For example, suppose you have + the following: + + a = 0; + /* Code that does not store to variable a. */ + a = 0; + + The compiler sees that the value of variable 'a' is already zero, so + it might well omit the second store. This would come as a fatal + surprise if some other CPU might have stored to variable 'a' in the + meantime. + + Use ACCESS_ONCE() to prevent the compiler from making this sort of + wrong guess: + + ACCESS_ONCE(a) = 0; + /* Code that does not store to variable a. */ + ACCESS_ONCE(a) = 0; + + (*) The compiler is within its rights to reorder memory accesses unless + you tell it not to. For example, consider the following interaction + between process-level code and an interrupt handler: + + void process_level(void) + { + msg = get_message(); + flag = true; + } + + void interrupt_handler(void) + { + if (flag) + process_message(msg); + } + + There is nothing to prevent the compiler from transforming + process_level() to the following, in fact, this might well be a + win for single-threaded code: + + void process_level(void) + { + flag = true; + msg = get_message(); + } + + If the interrupt occurs between these two statement, then + interrupt_handler() might be passed a garbled msg. Use ACCESS_ONCE() + to prevent this as follows: + + void process_level(void) + { + ACCESS_ONCE(msg) = get_message(); + ACCESS_ONCE(flag) = true; + } + + void interrupt_handler(void) + { + if (ACCESS_ONCE(flag)) + process_message(ACCESS_ONCE(msg)); + } + + Note that the ACCESS_ONCE() wrappers in interrupt_handler() + are needed if this interrupt handler can itself be interrupted + by something that also accesses 'flag' and 'msg', for example, + a nested interrupt or an NMI. Otherwise, ACCESS_ONCE() is not + needed in interrupt_handler() other than for documentation purposes. + (Note also that nested interrupts do not typically occur in modern + Linux kernels, in fact, if an interrupt handler returns with + interrupts enabled, you will get a WARN_ONCE() splat.) + + You should assume that the compiler can move ACCESS_ONCE() past + code not containing ACCESS_ONCE(), barrier(), or similar primitives. + + This effect could also be achieved using barrier(), but ACCESS_ONCE() + is more selective: With ACCESS_ONCE(), the compiler need only forget + the contents of the indicated memory locations, while with barrier() + the compiler must discard the value of all memory locations that + it has currented cached in any machine registers. Of course, + the compiler must also respect the order in which the ACCESS_ONCE()s + occur, though the CPU of course need not do so. + + (*) The compiler is within its rights to invent stores to a variable, + as in the following example: + + if (a) + b = a; + else + b = 42; + + The compiler might save a branch by optimizing this as follows: + + b = 42; + if (a) + b = a; + + In single-threaded code, this is not only safe, but also saves + a branch. Unfortunately, in concurrent code, this optimization + could cause some other CPU to see a spurious value of 42 -- even + if variable 'a' was never zero -- when loading variable 'b'. + Use ACCESS_ONCE() to prevent this as follows: + + if (a) + ACCESS_ONCE(b) = a; + else + ACCESS_ONCE(b) = 42; + + The compiler can also invent loads. These are usually less + damaging, but they can result in cache-line bouncing and thus in + poor performance and scalability. Use ACCESS_ONCE() to prevent + invented loads. + + (*) For aligned memory locations whose size allows them to be accessed + with a single memory-reference instruction, prevents "load tearing" + and "store tearing," in which a single large access is replaced by + multiple smaller accesses. For example, given an architecture having + 16-bit store instructions with 7-bit immediate fields, the compiler + might be tempted to use two 16-bit store-immediate instructions to + implement the following 32-bit store: + + p = 0x00010002; + + Please note that GCC really does use this sort of optimization, + which is not surprising given that it would likely take more + than two instructions to build the constant and then store it. + This optimization can therefore be a win in single-threaded code. + In fact, a recent bug (since fixed) caused GCC to incorrectly use + this optimization in a volatile store. In the absence of such bugs, + use of ACCESS_ONCE() prevents store tearing in the following example: + + ACCESS_ONCE(p) = 0x00010002; + + Use of packed structures can also result in load and store tearing, + as in this example: + + struct __attribute__((__packed__)) foo { + short a; + int b; + short c; + }; + struct foo foo1, foo2; + ... + + foo2.a = foo1.a; + foo2.b = foo1.b; + foo2.c = foo1.c; + + Because there are no ACCESS_ONCE() wrappers and no volatile markings, + the compiler would be well within its rights to implement these three + assignment statements as a pair of 32-bit loads followed by a pair + of 32-bit stores. This would result in load tearing on 'foo1.b' + and store tearing on 'foo2.b'. ACCESS_ONCE() again prevents tearing + in this example: + + foo2.a = foo1.a; + ACCESS_ONCE(foo2.b) = ACCESS_ONCE(foo1.b); + foo2.c = foo1.c; + +All that aside, it is never necessary to use ACCESS_ONCE() on a variable +that has been marked volatile. For example, because 'jiffies' is marked +volatile, it is never necessary to say ACCESS_ONCE(jiffies). The reason +for this is that ACCESS_ONCE() is implemented as a volatile cast, which +has no effect when its argument is already marked volatile. + +Please note that these compiler barriers have no direct effect on the CPU, +which may then reorder things however it wishes. + + +CPU MEMORY BARRIERS +------------------- + +The Linux kernel has eight basic CPU memory barriers: + + TYPE MANDATORY SMP CONDITIONAL + =============== ======================= =========================== + GENERAL mb() smp_mb() + WRITE wmb() smp_wmb() + READ rmb() smp_rmb() + DATA DEPENDENCY read_barrier_depends() smp_read_barrier_depends() + + +All memory barriers except the data dependency barriers imply a compiler +barrier. Data dependencies do not impose any additional compiler ordering. + +Aside: In the case of data dependencies, the compiler would be expected to +issue the loads in the correct order (eg. `a[b]` would have to load the value +of b before loading a[b]), however there is no guarantee in the C specification +that the compiler may not speculate the value of b (eg. is equal to 1) and load +a before b (eg. tmp = a[1]; if (b != 1) tmp = a[b]; ). There is also the +problem of a compiler reloading b after having loaded a[b], thus having a newer +copy of b than a[b]. A consensus has not yet been reached about these problems, +however the ACCESS_ONCE macro is a good place to start looking. + +SMP memory barriers are reduced to compiler barriers on uniprocessor compiled +systems because it is assumed that a CPU will appear to be self-consistent, +and will order overlapping accesses correctly with respect to itself. + +[!] Note that SMP memory barriers _must_ be used to control the ordering of +references to shared memory on SMP systems, though the use of locking instead +is sufficient. + +Mandatory barriers should not be used to control SMP effects, since mandatory +barriers unnecessarily impose overhead on UP systems. They may, however, be +used to control MMIO effects on accesses through relaxed memory I/O windows. +These are required even on non-SMP systems as they affect the order in which +memory operations appear to a device by prohibiting both the compiler and the +CPU from reordering them. + + +There are some more advanced barrier functions: + + (*) set_mb(var, value) + + This assigns the value to the variable and then inserts a full memory + barrier after it, depending on the function. It isn't guaranteed to + insert anything more than a compiler barrier in a UP compilation. + + + (*) smp_mb__before_atomic(); + (*) smp_mb__after_atomic(); + + These are for use with atomic (such as add, subtract, increment and + decrement) functions that don't return a value, especially when used for + reference counting. These functions do not imply memory barriers. + + These are also used for atomic bitop functions that do not return a + value (such as set_bit and clear_bit). + + As an example, consider a piece of code that marks an object as being dead + and then decrements the object's reference count: + + obj->dead = 1; + smp_mb__before_atomic(); + atomic_dec(&obj->ref_count); + + This makes sure that the death mark on the object is perceived to be set + *before* the reference counter is decremented. + + See Documentation/atomic_ops.txt for more information. See the "Atomic + operations" subsection for information on where to use these. + + + (*) dma_wmb(); + (*) dma_rmb(); + + These are for use with consistent memory to guarantee the ordering + of writes or reads of shared memory accessible to both the CPU and a + DMA capable device. + + For example, consider a device driver that shares memory with a device + and uses a descriptor status value to indicate if the descriptor belongs + to the device or the CPU, and a doorbell to notify it when new + descriptors are available: + + if (desc->status != DEVICE_OWN) { + /* do not read data until we own descriptor */ + dma_rmb(); + + /* read/modify data */ + read_data = desc->data; + desc->data = write_data; + + /* flush modifications before status update */ + dma_wmb(); + + /* assign ownership */ + desc->status = DEVICE_OWN; + + /* force memory to sync before notifying device via MMIO */ + wmb(); + + /* notify device of new descriptors */ + writel(DESC_NOTIFY, doorbell); + } + + The dma_rmb() allows us guarantee the device has released ownership + before we read the data from the descriptor, and the dma_wmb() allows + us to guarantee the data is written to the descriptor before the device + can see it now has ownership. The wmb() is needed to guarantee that the + cache coherent memory writes have completed before attempting a write to + the cache incoherent MMIO region. + + See Documentation/DMA-API.txt for more information on consistent memory. + +MMIO WRITE BARRIER +------------------ + +The Linux kernel also has a special barrier for use with memory-mapped I/O +writes: + + mmiowb(); + +This is a variation on the mandatory write barrier that causes writes to weakly +ordered I/O regions to be partially ordered. Its effects may go beyond the +CPU->Hardware interface and actually affect the hardware at some level. + +See the subsection "Locks vs I/O accesses" for more information. + + +=============================== +IMPLICIT KERNEL MEMORY BARRIERS +=============================== + +Some of the other functions in the linux kernel imply memory barriers, amongst +which are locking and scheduling functions. + +This specification is a _minimum_ guarantee; any particular architecture may +provide more substantial guarantees, but these may not be relied upon outside +of arch specific code. + + +ACQUIRING FUNCTIONS +------------------- + +The Linux kernel has a number of locking constructs: + + (*) spin locks + (*) R/W spin locks + (*) mutexes + (*) semaphores + (*) R/W semaphores + (*) RCU + +In all cases there are variants on "ACQUIRE" operations and "RELEASE" operations +for each construct. These operations all imply certain barriers: + + (1) ACQUIRE operation implication: + + Memory operations issued after the ACQUIRE will be completed after the + ACQUIRE operation has completed. + + Memory operations issued before the ACQUIRE may be completed after + the ACQUIRE operation has completed. An smp_mb__before_spinlock(), + combined with a following ACQUIRE, orders prior loads against + subsequent loads and stores and also orders prior stores against + subsequent stores. Note that this is weaker than smp_mb()! The + smp_mb__before_spinlock() primitive is free on many architectures. + + (2) RELEASE operation implication: + + Memory operations issued before the RELEASE will be completed before the + RELEASE operation has completed. + + Memory operations issued after the RELEASE may be completed before the + RELEASE operation has completed. + + (3) ACQUIRE vs ACQUIRE implication: + + All ACQUIRE operations issued before another ACQUIRE operation will be + completed before that ACQUIRE operation. + + (4) ACQUIRE vs RELEASE implication: + + All ACQUIRE operations issued before a RELEASE operation will be + completed before the RELEASE operation. + + (5) Failed conditional ACQUIRE implication: + + Certain locking variants of the ACQUIRE operation may fail, either due to + being unable to get the lock immediately, or due to receiving an unblocked + signal whilst asleep waiting for the lock to become available. Failed + locks do not imply any sort of barrier. + +[!] Note: one of the consequences of lock ACQUIREs and RELEASEs being only +one-way barriers is that the effects of instructions outside of a critical +section may seep into the inside of the critical section. + +An ACQUIRE followed by a RELEASE may not be assumed to be full memory barrier +because it is possible for an access preceding the ACQUIRE to happen after the +ACQUIRE, and an access following the RELEASE to happen before the RELEASE, and +the two accesses can themselves then cross: + + *A = a; + ACQUIRE M + RELEASE M + *B = b; + +may occur as: + + ACQUIRE M, STORE *B, STORE *A, RELEASE M + +When the ACQUIRE and RELEASE are a lock acquisition and release, +respectively, this same reordering can occur if the lock's ACQUIRE and +RELEASE are to the same lock variable, but only from the perspective of +another CPU not holding that lock. In short, a ACQUIRE followed by an +RELEASE may -not- be assumed to be a full memory barrier. + +Similarly, the reverse case of a RELEASE followed by an ACQUIRE does not +imply a full memory barrier. If it is necessary for a RELEASE-ACQUIRE +pair to produce a full barrier, the ACQUIRE can be followed by an +smp_mb__after_unlock_lock() invocation. This will produce a full barrier +if either (a) the RELEASE and the ACQUIRE are executed by the same +CPU or task, or (b) the RELEASE and ACQUIRE act on the same variable. +The smp_mb__after_unlock_lock() primitive is free on many architectures. +Without smp_mb__after_unlock_lock(), the CPU's execution of the critical +sections corresponding to the RELEASE and the ACQUIRE can cross, so that: + + *A = a; + RELEASE M + ACQUIRE N + *B = b; + +could occur as: + + ACQUIRE N, STORE *B, STORE *A, RELEASE M + +It might appear that this reordering could introduce a deadlock. +However, this cannot happen because if such a deadlock threatened, +the RELEASE would simply complete, thereby avoiding the deadlock. + + Why does this work? + + One key point is that we are only talking about the CPU doing + the reordering, not the compiler. If the compiler (or, for + that matter, the developer) switched the operations, deadlock + -could- occur. + + But suppose the CPU reordered the operations. In this case, + the unlock precedes the lock in the assembly code. The CPU + simply elected to try executing the later lock operation first. + If there is a deadlock, this lock operation will simply spin (or + try to sleep, but more on that later). The CPU will eventually + execute the unlock operation (which preceded the lock operation + in the assembly code), which will unravel the potential deadlock, + allowing the lock operation to succeed. + + But what if the lock is a sleeplock? In that case, the code will + try to enter the scheduler, where it will eventually encounter + a memory barrier, which will force the earlier unlock operation + to complete, again unraveling the deadlock. There might be + a sleep-unlock race, but the locking primitive needs to resolve + such races properly in any case. + +With smp_mb__after_unlock_lock(), the two critical sections cannot overlap. +For example, with the following code, the store to *A will always be +seen by other CPUs before the store to *B: + + *A = a; + RELEASE M + ACQUIRE N + smp_mb__after_unlock_lock(); + *B = b; + +The operations will always occur in one of the following orders: + + STORE *A, RELEASE, ACQUIRE, smp_mb__after_unlock_lock(), STORE *B + STORE *A, ACQUIRE, RELEASE, smp_mb__after_unlock_lock(), STORE *B + ACQUIRE, STORE *A, RELEASE, smp_mb__after_unlock_lock(), STORE *B + +If the RELEASE and ACQUIRE were instead both operating on the same lock +variable, only the first of these alternatives can occur. In addition, +the more strongly ordered systems may rule out some of the above orders. +But in any case, as noted earlier, the smp_mb__after_unlock_lock() +ensures that the store to *A will always be seen as happening before +the store to *B. + +Locks and semaphores may not provide any guarantee of ordering on UP compiled +systems, and so cannot be counted on in such a situation to actually achieve +anything at all - especially with respect to I/O accesses - unless combined +with interrupt disabling operations. + +See also the section on "Inter-CPU locking barrier effects". + + +As an example, consider the following: + + *A = a; + *B = b; + ACQUIRE + *C = c; + *D = d; + RELEASE + *E = e; + *F = f; + +The following sequence of events is acceptable: + + ACQUIRE, {*F,*A}, *E, {*C,*D}, *B, RELEASE + + [+] Note that {*F,*A} indicates a combined access. + +But none of the following are: + + {*F,*A}, *B, ACQUIRE, *C, *D, RELEASE, *E + *A, *B, *C, ACQUIRE, *D, RELEASE, *E, *F + *A, *B, ACQUIRE, *C, RELEASE, *D, *E, *F + *B, ACQUIRE, *C, *D, RELEASE, {*F,*A}, *E + + + +INTERRUPT DISABLING FUNCTIONS +----------------------------- + +Functions that disable interrupts (ACQUIRE equivalent) and enable interrupts +(RELEASE equivalent) will act as compiler barriers only. So if memory or I/O +barriers are required in such a situation, they must be provided from some +other means. + + +SLEEP AND WAKE-UP FUNCTIONS +--------------------------- + +Sleeping and waking on an event flagged in global data can be viewed as an +interaction between two pieces of data: the task state of the task waiting for +the event and the global data used to indicate the event. To make sure that +these appear to happen in the right order, the primitives to begin the process +of going to sleep, and the primitives to initiate a wake up imply certain +barriers. + +Firstly, the sleeper normally follows something like this sequence of events: + + for (;;) { + set_current_state(TASK_UNINTERRUPTIBLE); + if (event_indicated) + break; + schedule(); + } + +A general memory barrier is interpolated automatically by set_current_state() +after it has altered the task state: + + CPU 1 + =============================== + set_current_state(); + set_mb(); + STORE current->state + <general barrier> + LOAD event_indicated + +set_current_state() may be wrapped by: + + prepare_to_wait(); + prepare_to_wait_exclusive(); + +which therefore also imply a general memory barrier after setting the state. +The whole sequence above is available in various canned forms, all of which +interpolate the memory barrier in the right place: + + wait_event(); + wait_event_interruptible(); + wait_event_interruptible_exclusive(); + wait_event_interruptible_timeout(); + wait_event_killable(); + wait_event_timeout(); + wait_on_bit(); + wait_on_bit_lock(); + + +Secondly, code that performs a wake up normally follows something like this: + + event_indicated = 1; + wake_up(&event_wait_queue); + +or: + + event_indicated = 1; + wake_up_process(event_daemon); + +A write memory barrier is implied by wake_up() and co. if and only if they wake +something up. The barrier occurs before the task state is cleared, and so sits +between the STORE to indicate the event and the STORE to set TASK_RUNNING: + + CPU 1 CPU 2 + =============================== =============================== + set_current_state(); STORE event_indicated + set_mb(); wake_up(); + STORE current->state <write barrier> + <general barrier> STORE current->state + LOAD event_indicated + +To repeat, this write memory barrier is present if and only if something +is actually awakened. To see this, consider the following sequence of +events, where X and Y are both initially zero: + + CPU 1 CPU 2 + =============================== =============================== + X = 1; STORE event_indicated + smp_mb(); wake_up(); + Y = 1; wait_event(wq, Y == 1); + wake_up(); load from Y sees 1, no memory barrier + load from X might see 0 + +In contrast, if a wakeup does occur, CPU 2's load from X would be guaranteed +to see 1. + +The available waker functions include: + + complete(); + wake_up(); + wake_up_all(); + wake_up_bit(); + wake_up_interruptible(); + wake_up_interruptible_all(); + wake_up_interruptible_nr(); + wake_up_interruptible_poll(); + wake_up_interruptible_sync(); + wake_up_interruptible_sync_poll(); + wake_up_locked(); + wake_up_locked_poll(); + wake_up_nr(); + wake_up_poll(); + wake_up_process(); + + +[!] Note that the memory barriers implied by the sleeper and the waker do _not_ +order multiple stores before the wake-up with respect to loads of those stored +values after the sleeper has called set_current_state(). For instance, if the +sleeper does: + + set_current_state(TASK_INTERRUPTIBLE); + if (event_indicated) + break; + __set_current_state(TASK_RUNNING); + do_something(my_data); + +and the waker does: + + my_data = value; + event_indicated = 1; + wake_up(&event_wait_queue); + +there's no guarantee that the change to event_indicated will be perceived by +the sleeper as coming after the change to my_data. In such a circumstance, the +code on both sides must interpolate its own memory barriers between the +separate data accesses. Thus the above sleeper ought to do: + + set_current_state(TASK_INTERRUPTIBLE); + if (event_indicated) { + smp_rmb(); + do_something(my_data); + } + +and the waker should do: + + my_data = value; + smp_wmb(); + event_indicated = 1; + wake_up(&event_wait_queue); + + +MISCELLANEOUS FUNCTIONS +----------------------- + +Other functions that imply barriers: + + (*) schedule() and similar imply full memory barriers. + + +=================================== +INTER-CPU ACQUIRING BARRIER EFFECTS +=================================== + +On SMP systems locking primitives give a more substantial form of barrier: one +that does affect memory access ordering on other CPUs, within the context of +conflict on any particular lock. + + +ACQUIRES VS MEMORY ACCESSES +--------------------------- + +Consider the following: the system has a pair of spinlocks (M) and (Q), and +three CPUs; then should the following sequence of events occur: + + CPU 1 CPU 2 + =============================== =============================== + ACCESS_ONCE(*A) = a; ACCESS_ONCE(*E) = e; + ACQUIRE M ACQUIRE Q + ACCESS_ONCE(*B) = b; ACCESS_ONCE(*F) = f; + ACCESS_ONCE(*C) = c; ACCESS_ONCE(*G) = g; + RELEASE M RELEASE Q + ACCESS_ONCE(*D) = d; ACCESS_ONCE(*H) = h; + +Then there is no guarantee as to what order CPU 3 will see the accesses to *A +through *H occur in, other than the constraints imposed by the separate locks +on the separate CPUs. It might, for example, see: + + *E, ACQUIRE M, ACQUIRE Q, *G, *C, *F, *A, *B, RELEASE Q, *D, *H, RELEASE M + +But it won't see any of: + + *B, *C or *D preceding ACQUIRE M + *A, *B or *C following RELEASE M + *F, *G or *H preceding ACQUIRE Q + *E, *F or *G following RELEASE Q + + +However, if the following occurs: + + CPU 1 CPU 2 + =============================== =============================== + ACCESS_ONCE(*A) = a; + ACQUIRE M [1] + ACCESS_ONCE(*B) = b; + ACCESS_ONCE(*C) = c; + RELEASE M [1] + ACCESS_ONCE(*D) = d; ACCESS_ONCE(*E) = e; + ACQUIRE M [2] + smp_mb__after_unlock_lock(); + ACCESS_ONCE(*F) = f; + ACCESS_ONCE(*G) = g; + RELEASE M [2] + ACCESS_ONCE(*H) = h; + +CPU 3 might see: + + *E, ACQUIRE M [1], *C, *B, *A, RELEASE M [1], + ACQUIRE M [2], *H, *F, *G, RELEASE M [2], *D + +But assuming CPU 1 gets the lock first, CPU 3 won't see any of: + + *B, *C, *D, *F, *G or *H preceding ACQUIRE M [1] + *A, *B or *C following RELEASE M [1] + *F, *G or *H preceding ACQUIRE M [2] + *A, *B, *C, *E, *F or *G following RELEASE M [2] + +Note that the smp_mb__after_unlock_lock() is critically important +here: Without it CPU 3 might see some of the above orderings. +Without smp_mb__after_unlock_lock(), the accesses are not guaranteed +to be seen in order unless CPU 3 holds lock M. + + +ACQUIRES VS I/O ACCESSES +------------------------ + +Under certain circumstances (especially involving NUMA), I/O accesses within +two spinlocked sections on two different CPUs may be seen as interleaved by the +PCI bridge, because the PCI bridge does not necessarily participate in the +cache-coherence protocol, and is therefore incapable of issuing the required +read memory barriers. + +For example: + + CPU 1 CPU 2 + =============================== =============================== + spin_lock(Q) + writel(0, ADDR) + writel(1, DATA); + spin_unlock(Q); + spin_lock(Q); + writel(4, ADDR); + writel(5, DATA); + spin_unlock(Q); + +may be seen by the PCI bridge as follows: + + STORE *ADDR = 0, STORE *ADDR = 4, STORE *DATA = 1, STORE *DATA = 5 + +which would probably cause the hardware to malfunction. + + +What is necessary here is to intervene with an mmiowb() before dropping the +spinlock, for example: + + CPU 1 CPU 2 + =============================== =============================== + spin_lock(Q) + writel(0, ADDR) + writel(1, DATA); + mmiowb(); + spin_unlock(Q); + spin_lock(Q); + writel(4, ADDR); + writel(5, DATA); + mmiowb(); + spin_unlock(Q); + +this will ensure that the two stores issued on CPU 1 appear at the PCI bridge +before either of the stores issued on CPU 2. + + +Furthermore, following a store by a load from the same device obviates the need +for the mmiowb(), because the load forces the store to complete before the load +is performed: + + CPU 1 CPU 2 + =============================== =============================== + spin_lock(Q) + writel(0, ADDR) + a = readl(DATA); + spin_unlock(Q); + spin_lock(Q); + writel(4, ADDR); + b = readl(DATA); + spin_unlock(Q); + + +See Documentation/DocBook/deviceiobook.tmpl for more information. + + +================================= +WHERE ARE MEMORY BARRIERS NEEDED? +================================= + +Under normal operation, memory operation reordering is generally not going to +be a problem as a single-threaded linear piece of code will still appear to +work correctly, even if it's in an SMP kernel. There are, however, four +circumstances in which reordering definitely _could_ be a problem: + + (*) Interprocessor interaction. + + (*) Atomic operations. + + (*) Accessing devices. + + (*) Interrupts. + + +INTERPROCESSOR INTERACTION +-------------------------- + +When there's a system with more than one processor, more than one CPU in the +system may be working on the same data set at the same time. This can cause +synchronisation problems, and the usual way of dealing with them is to use +locks. Locks, however, are quite expensive, and so it may be preferable to +operate without the use of a lock if at all possible. In such a case +operations that affect both CPUs may have to be carefully ordered to prevent +a malfunction. + +Consider, for example, the R/W semaphore slow path. Here a waiting process is +queued on the semaphore, by virtue of it having a piece of its stack linked to +the semaphore's list of waiting processes: + + struct rw_semaphore { + ... + spinlock_t lock; + struct list_head waiters; + }; + + struct rwsem_waiter { + struct list_head list; + struct task_struct *task; + }; + +To wake up a particular waiter, the up_read() or up_write() functions have to: + + (1) read the next pointer from this waiter's record to know as to where the + next waiter record is; + + (2) read the pointer to the waiter's task structure; + + (3) clear the task pointer to tell the waiter it has been given the semaphore; + + (4) call wake_up_process() on the task; and + + (5) release the reference held on the waiter's task struct. + +In other words, it has to perform this sequence of events: + + LOAD waiter->list.next; + LOAD waiter->task; + STORE waiter->task; + CALL wakeup + RELEASE task + +and if any of these steps occur out of order, then the whole thing may +malfunction. + +Once it has queued itself and dropped the semaphore lock, the waiter does not +get the lock again; it instead just waits for its task pointer to be cleared +before proceeding. Since the record is on the waiter's stack, this means that +if the task pointer is cleared _before_ the next pointer in the list is read, +another CPU might start processing the waiter and might clobber the waiter's +stack before the up*() function has a chance to read the next pointer. + +Consider then what might happen to the above sequence of events: + + CPU 1 CPU 2 + =============================== =============================== + down_xxx() + Queue waiter + Sleep + up_yyy() + LOAD waiter->task; + STORE waiter->task; + Woken up by other event + <preempt> + Resume processing + down_xxx() returns + call foo() + foo() clobbers *waiter + </preempt> + LOAD waiter->list.next; + --- OOPS --- + +This could be dealt with using the semaphore lock, but then the down_xxx() +function has to needlessly get the spinlock again after being woken up. + +The way to deal with this is to insert a general SMP memory barrier: + + LOAD waiter->list.next; + LOAD waiter->task; + smp_mb(); + STORE waiter->task; + CALL wakeup + RELEASE task + +In this case, the barrier makes a guarantee that all memory accesses before the +barrier will appear to happen before all the memory accesses after the barrier +with respect to the other CPUs on the system. It does _not_ guarantee that all +the memory accesses before the barrier will be complete by the time the barrier +instruction itself is complete. + +On a UP system - where this wouldn't be a problem - the smp_mb() is just a +compiler barrier, thus making sure the compiler emits the instructions in the +right order without actually intervening in the CPU. Since there's only one +CPU, that CPU's dependency ordering logic will take care of everything else. + + +ATOMIC OPERATIONS +----------------- + +Whilst they are technically interprocessor interaction considerations, atomic +operations are noted specially as some of them imply full memory barriers and +some don't, but they're very heavily relied on as a group throughout the +kernel. + +Any atomic operation that modifies some state in memory and returns information +about the state (old or new) implies an SMP-conditional general memory barrier +(smp_mb()) on each side of the actual operation (with the exception of +explicit lock operations, described later). These include: + + xchg(); + cmpxchg(); + atomic_xchg(); atomic_long_xchg(); + atomic_cmpxchg(); atomic_long_cmpxchg(); + atomic_inc_return(); atomic_long_inc_return(); + atomic_dec_return(); atomic_long_dec_return(); + atomic_add_return(); atomic_long_add_return(); + atomic_sub_return(); atomic_long_sub_return(); + atomic_inc_and_test(); atomic_long_inc_and_test(); + atomic_dec_and_test(); atomic_long_dec_and_test(); + atomic_sub_and_test(); atomic_long_sub_and_test(); + atomic_add_negative(); atomic_long_add_negative(); + test_and_set_bit(); + test_and_clear_bit(); + test_and_change_bit(); + + /* when succeeds (returns 1) */ + atomic_add_unless(); atomic_long_add_unless(); + +These are used for such things as implementing ACQUIRE-class and RELEASE-class +operations and adjusting reference counters towards object destruction, and as +such the implicit memory barrier effects are necessary. + + +The following operations are potential problems as they do _not_ imply memory +barriers, but might be used for implementing such things as RELEASE-class +operations: + + atomic_set(); + set_bit(); + clear_bit(); + change_bit(); + +With these the appropriate explicit memory barrier should be used if necessary +(smp_mb__before_atomic() for instance). + + +The following also do _not_ imply memory barriers, and so may require explicit +memory barriers under some circumstances (smp_mb__before_atomic() for +instance): + + atomic_add(); + atomic_sub(); + atomic_inc(); + atomic_dec(); + +If they're used for statistics generation, then they probably don't need memory +barriers, unless there's a coupling between statistical data. + +If they're used for reference counting on an object to control its lifetime, +they probably don't need memory barriers because either the reference count +will be adjusted inside a locked section, or the caller will already hold +sufficient references to make the lock, and thus a memory barrier unnecessary. + +If they're used for constructing a lock of some description, then they probably +do need memory barriers as a lock primitive generally has to do things in a +specific order. + +Basically, each usage case has to be carefully considered as to whether memory +barriers are needed or not. + +The following operations are special locking primitives: + + test_and_set_bit_lock(); + clear_bit_unlock(); + __clear_bit_unlock(); + +These implement ACQUIRE-class and RELEASE-class operations. These should be used in +preference to other operations when implementing locking primitives, because +their implementations can be optimised on many architectures. + +[!] Note that special memory barrier primitives are available for these +situations because on some CPUs the atomic instructions used imply full memory +barriers, and so barrier instructions are superfluous in conjunction with them, +and in such cases the special barrier primitives will be no-ops. + +See Documentation/atomic_ops.txt for more information. + + +ACCESSING DEVICES +----------------- + +Many devices can be memory mapped, and so appear to the CPU as if they're just +a set of memory locations. To control such a device, the driver usually has to +make the right memory accesses in exactly the right order. + +However, having a clever CPU or a clever compiler creates a potential problem +in that the carefully sequenced accesses in the driver code won't reach the +device in the requisite order if the CPU or the compiler thinks it is more +efficient to reorder, combine or merge accesses - something that would cause +the device to malfunction. + +Inside of the Linux kernel, I/O should be done through the appropriate accessor +routines - such as inb() or writel() - which know how to make such accesses +appropriately sequential. Whilst this, for the most part, renders the explicit +use of memory barriers unnecessary, there are a couple of situations where they +might be needed: + + (1) On some systems, I/O stores are not strongly ordered across all CPUs, and + so for _all_ general drivers locks should be used and mmiowb() must be + issued prior to unlocking the critical section. + + (2) If the accessor functions are used to refer to an I/O memory window with + relaxed memory access properties, then _mandatory_ memory barriers are + required to enforce ordering. + +See Documentation/DocBook/deviceiobook.tmpl for more information. + + +INTERRUPTS +---------- + +A driver may be interrupted by its own interrupt service routine, and thus the +two parts of the driver may interfere with each other's attempts to control or +access the device. + +This may be alleviated - at least in part - by disabling local interrupts (a +form of locking), such that the critical operations are all contained within +the interrupt-disabled section in the driver. Whilst the driver's interrupt +routine is executing, the driver's core may not run on the same CPU, and its +interrupt is not permitted to happen again until the current interrupt has been +handled, thus the interrupt handler does not need to lock against that. + +However, consider a driver that was talking to an ethernet card that sports an +address register and a data register. If that driver's core talks to the card +under interrupt-disablement and then the driver's interrupt handler is invoked: + + LOCAL IRQ DISABLE + writew(ADDR, 3); + writew(DATA, y); + LOCAL IRQ ENABLE + <interrupt> + writew(ADDR, 4); + q = readw(DATA); + </interrupt> + +The store to the data register might happen after the second store to the +address register if ordering rules are sufficiently relaxed: + + STORE *ADDR = 3, STORE *ADDR = 4, STORE *DATA = y, q = LOAD *DATA + + +If ordering rules are relaxed, it must be assumed that accesses done inside an +interrupt disabled section may leak outside of it and may interleave with +accesses performed in an interrupt - and vice versa - unless implicit or +explicit barriers are used. + +Normally this won't be a problem because the I/O accesses done inside such +sections will include synchronous load operations on strictly ordered I/O +registers that form implicit I/O barriers. If this isn't sufficient then an +mmiowb() may need to be used explicitly. + + +A similar situation may occur between an interrupt routine and two routines +running on separate CPUs that communicate with each other. If such a case is +likely, then interrupt-disabling locks should be used to guarantee ordering. + + +========================== +KERNEL I/O BARRIER EFFECTS +========================== + +When accessing I/O memory, drivers should use the appropriate accessor +functions: + + (*) inX(), outX(): + + These are intended to talk to I/O space rather than memory space, but + that's primarily a CPU-specific concept. The i386 and x86_64 processors do + indeed have special I/O space access cycles and instructions, but many + CPUs don't have such a concept. + + The PCI bus, amongst others, defines an I/O space concept which - on such + CPUs as i386 and x86_64 - readily maps to the CPU's concept of I/O + space. However, it may also be mapped as a virtual I/O space in the CPU's + memory map, particularly on those CPUs that don't support alternate I/O + spaces. + + Accesses to this space may be fully synchronous (as on i386), but + intermediary bridges (such as the PCI host bridge) may not fully honour + that. + + They are guaranteed to be fully ordered with respect to each other. + + They are not guaranteed to be fully ordered with respect to other types of + memory and I/O operation. + + (*) readX(), writeX(): + + Whether these are guaranteed to be fully ordered and uncombined with + respect to each other on the issuing CPU depends on the characteristics + defined for the memory window through which they're accessing. On later + i386 architecture machines, for example, this is controlled by way of the + MTRR registers. + + Ordinarily, these will be guaranteed to be fully ordered and uncombined, + provided they're not accessing a prefetchable device. + + However, intermediary hardware (such as a PCI bridge) may indulge in + deferral if it so wishes; to flush a store, a load from the same location + is preferred[*], but a load from the same device or from configuration + space should suffice for PCI. + + [*] NOTE! attempting to load from the same location as was written to may + cause a malfunction - consider the 16550 Rx/Tx serial registers for + example. + + Used with prefetchable I/O memory, an mmiowb() barrier may be required to + force stores to be ordered. + + Please refer to the PCI specification for more information on interactions + between PCI transactions. + + (*) readX_relaxed(), writeX_relaxed() + + These are similar to readX() and writeX(), but provide weaker memory + ordering guarantees. Specifically, they do not guarantee ordering with + respect to normal memory accesses (e.g. DMA buffers) nor do they guarantee + ordering with respect to LOCK or UNLOCK operations. If the latter is + required, an mmiowb() barrier can be used. Note that relaxed accesses to + the same peripheral are guaranteed to be ordered with respect to each + other. + + (*) ioreadX(), iowriteX() + + These will perform appropriately for the type of access they're actually + doing, be it inX()/outX() or readX()/writeX(). + + +======================================== +ASSUMED MINIMUM EXECUTION ORDERING MODEL +======================================== + +It has to be assumed that the conceptual CPU is weakly-ordered but that it will +maintain the appearance of program causality with respect to itself. Some CPUs +(such as i386 or x86_64) are more constrained than others (such as powerpc or +frv), and so the most relaxed case (namely DEC Alpha) must be assumed outside +of arch-specific code. + +This means that it must be considered that the CPU will execute its instruction +stream in any order it feels like - or even in parallel - provided that if an +instruction in the stream depends on an earlier instruction, then that +earlier instruction must be sufficiently complete[*] before the later +instruction may proceed; in other words: provided that the appearance of +causality is maintained. + + [*] Some instructions have more than one effect - such as changing the + condition codes, changing registers or changing memory - and different + instructions may depend on different effects. + +A CPU may also discard any instruction sequence that winds up having no +ultimate effect. For example, if two adjacent instructions both load an +immediate value into the same register, the first may be discarded. + + +Similarly, it has to be assumed that compiler might reorder the instruction +stream in any way it sees fit, again provided the appearance of causality is +maintained. + + +============================ +THE EFFECTS OF THE CPU CACHE +============================ + +The way cached memory operations are perceived across the system is affected to +a certain extent by the caches that lie between CPUs and memory, and by the +memory coherence system that maintains the consistency of state in the system. + +As far as the way a CPU interacts with another part of the system through the +caches goes, the memory system has to include the CPU's caches, and memory +barriers for the most part act at the interface between the CPU and its cache +(memory barriers logically act on the dotted line in the following diagram): + + <--- CPU ---> : <----------- Memory -----------> + : + +--------+ +--------+ : +--------+ +-----------+ + | | | | : | | | | +--------+ + | CPU | | Memory | : | CPU | | | | | + | Core |--->| Access |----->| Cache |<-->| | | | + | | | Queue | : | | | |--->| Memory | + | | | | : | | | | | | + +--------+ +--------+ : +--------+ | | | | + : | Cache | +--------+ + : | Coherency | + : | Mechanism | +--------+ + +--------+ +--------+ : +--------+ | | | | + | | | | : | | | | | | + | CPU | | Memory | : | CPU | | |--->| Device | + | Core |--->| Access |----->| Cache |<-->| | | | + | | | Queue | : | | | | | | + | | | | : | | | | +--------+ + +--------+ +--------+ : +--------+ +-----------+ + : + : + +Although any particular load or store may not actually appear outside of the +CPU that issued it since it may have been satisfied within the CPU's own cache, +it will still appear as if the full memory access had taken place as far as the +other CPUs are concerned since the cache coherency mechanisms will migrate the +cacheline over to the accessing CPU and propagate the effects upon conflict. + +The CPU core may execute instructions in any order it deems fit, provided the +expected program causality appears to be maintained. Some of the instructions +generate load and store operations which then go into the queue of memory +accesses to be performed. The core may place these in the queue in any order +it wishes, and continue execution until it is forced to wait for an instruction +to complete. + +What memory barriers are concerned with is controlling the order in which +accesses cross from the CPU side of things to the memory side of things, and +the order in which the effects are perceived to happen by the other observers +in the system. + +[!] Memory barriers are _not_ needed within a given CPU, as CPUs always see +their own loads and stores as if they had happened in program order. + +[!] MMIO or other device accesses may bypass the cache system. This depends on +the properties of the memory window through which devices are accessed and/or +the use of any special device communication instructions the CPU may have. + + +CACHE COHERENCY +--------------- + +Life isn't quite as simple as it may appear above, however: for while the +caches are expected to be coherent, there's no guarantee that that coherency +will be ordered. This means that whilst changes made on one CPU will +eventually become visible on all CPUs, there's no guarantee that they will +become apparent in the same order on those other CPUs. + + +Consider dealing with a system that has a pair of CPUs (1 & 2), each of which +has a pair of parallel data caches (CPU 1 has A/B, and CPU 2 has C/D): + + : + : +--------+ + : +---------+ | | + +--------+ : +--->| Cache A |<------->| | + | | : | +---------+ | | + | CPU 1 |<---+ | | + | | : | +---------+ | | + +--------+ : +--->| Cache B |<------->| | + : +---------+ | | + : | Memory | + : +---------+ | System | + +--------+ : +--->| Cache C |<------->| | + | | : | +---------+ | | + | CPU 2 |<---+ | | + | | : | +---------+ | | + +--------+ : +--->| Cache D |<------->| | + : +---------+ | | + : +--------+ + : + +Imagine the system has the following properties: + + (*) an odd-numbered cache line may be in cache A, cache C or it may still be + resident in memory; + + (*) an even-numbered cache line may be in cache B, cache D or it may still be + resident in memory; + + (*) whilst the CPU core is interrogating one cache, the other cache may be + making use of the bus to access the rest of the system - perhaps to + displace a dirty cacheline or to do a speculative load; + + (*) each cache has a queue of operations that need to be applied to that cache + to maintain coherency with the rest of the system; + + (*) the coherency queue is not flushed by normal loads to lines already + present in the cache, even though the contents of the queue may + potentially affect those loads. + +Imagine, then, that two writes are made on the first CPU, with a write barrier +between them to guarantee that they will appear to reach that CPU's caches in +the requisite order: + + CPU 1 CPU 2 COMMENT + =============== =============== ======================================= + u == 0, v == 1 and p == &u, q == &u + v = 2; + smp_wmb(); Make sure change to v is visible before + change to p + <A:modify v=2> v is now in cache A exclusively + p = &v; + <B:modify p=&v> p is now in cache B exclusively + +The write memory barrier forces the other CPUs in the system to perceive that +the local CPU's caches have apparently been updated in the correct order. But +now imagine that the second CPU wants to read those values: + + CPU 1 CPU 2 COMMENT + =============== =============== ======================================= + ... + q = p; + x = *q; + +The above pair of reads may then fail to happen in the expected order, as the +cacheline holding p may get updated in one of the second CPU's caches whilst +the update to the cacheline holding v is delayed in the other of the second +CPU's caches by some other cache event: + + CPU 1 CPU 2 COMMENT + =============== =============== ======================================= + u == 0, v == 1 and p == &u, q == &u + v = 2; + smp_wmb(); + <A:modify v=2> <C:busy> + <C:queue v=2> + p = &v; q = p; + <D:request p> + <B:modify p=&v> <D:commit p=&v> + <D:read p> + x = *q; + <C:read *q> Reads from v before v updated in cache + <C:unbusy> + <C:commit v=2> + +Basically, whilst both cachelines will be updated on CPU 2 eventually, there's +no guarantee that, without intervention, the order of update will be the same +as that committed on CPU 1. + + +To intervene, we need to interpolate a data dependency barrier or a read +barrier between the loads. This will force the cache to commit its coherency +queue before processing any further requests: + + CPU 1 CPU 2 COMMENT + =============== =============== ======================================= + u == 0, v == 1 and p == &u, q == &u + v = 2; + smp_wmb(); + <A:modify v=2> <C:busy> + <C:queue v=2> + p = &v; q = p; + <D:request p> + <B:modify p=&v> <D:commit p=&v> + <D:read p> + smp_read_barrier_depends() + <C:unbusy> + <C:commit v=2> + x = *q; + <C:read *q> Reads from v after v updated in cache + + +This sort of problem can be encountered on DEC Alpha processors as they have a +split cache that improves performance by making better use of the data bus. +Whilst most CPUs do imply a data dependency barrier on the read when a memory +access depends on a read, not all do, so it may not be relied on. + +Other CPUs may also have split caches, but must coordinate between the various +cachelets for normal memory accesses. The semantics of the Alpha removes the +need for coordination in the absence of memory barriers. + + +CACHE COHERENCY VS DMA +---------------------- + +Not all systems maintain cache coherency with respect to devices doing DMA. In +such cases, a device attempting DMA may obtain stale data from RAM because +dirty cache lines may be resident in the caches of various CPUs, and may not +have been written back to RAM yet. To deal with this, the appropriate part of +the kernel must flush the overlapping bits of cache on each CPU (and maybe +invalidate them as well). + +In addition, the data DMA'd to RAM by a device may be overwritten by dirty +cache lines being written back to RAM from a CPU's cache after the device has +installed its own data, or cache lines present in the CPU's cache may simply +obscure the fact that RAM has been updated, until at such time as the cacheline +is discarded from the CPU's cache and reloaded. To deal with this, the +appropriate part of the kernel must invalidate the overlapping bits of the +cache on each CPU. + +See Documentation/cachetlb.txt for more information on cache management. + + +CACHE COHERENCY VS MMIO +----------------------- + +Memory mapped I/O usually takes place through memory locations that are part of +a window in the CPU's memory space that has different properties assigned than +the usual RAM directed window. + +Amongst these properties is usually the fact that such accesses bypass the +caching entirely and go directly to the device buses. This means MMIO accesses +may, in effect, overtake accesses to cached memory that were emitted earlier. +A memory barrier isn't sufficient in such a case, but rather the cache must be +flushed between the cached memory write and the MMIO access if the two are in +any way dependent. + + +========================= +THE THINGS CPUS GET UP TO +========================= + +A programmer might take it for granted that the CPU will perform memory +operations in exactly the order specified, so that if the CPU is, for example, +given the following piece of code to execute: + + a = ACCESS_ONCE(*A); + ACCESS_ONCE(*B) = b; + c = ACCESS_ONCE(*C); + d = ACCESS_ONCE(*D); + ACCESS_ONCE(*E) = e; + +they would then expect that the CPU will complete the memory operation for each +instruction before moving on to the next one, leading to a definite sequence of +operations as seen by external observers in the system: + + LOAD *A, STORE *B, LOAD *C, LOAD *D, STORE *E. + + +Reality is, of course, much messier. With many CPUs and compilers, the above +assumption doesn't hold because: + + (*) loads are more likely to need to be completed immediately to permit + execution progress, whereas stores can often be deferred without a + problem; + + (*) loads may be done speculatively, and the result discarded should it prove + to have been unnecessary; + + (*) loads may be done speculatively, leading to the result having been fetched + at the wrong time in the expected sequence of events; + + (*) the order of the memory accesses may be rearranged to promote better use + of the CPU buses and caches; + + (*) loads and stores may be combined to improve performance when talking to + memory or I/O hardware that can do batched accesses of adjacent locations, + thus cutting down on transaction setup costs (memory and PCI devices may + both be able to do this); and + + (*) the CPU's data cache may affect the ordering, and whilst cache-coherency + mechanisms may alleviate this - once the store has actually hit the cache + - there's no guarantee that the coherency management will be propagated in + order to other CPUs. + +So what another CPU, say, might actually observe from the above piece of code +is: + + LOAD *A, ..., LOAD {*C,*D}, STORE *E, STORE *B + + (Where "LOAD {*C,*D}" is a combined load) + + +However, it is guaranteed that a CPU will be self-consistent: it will see its +_own_ accesses appear to be correctly ordered, without the need for a memory +barrier. For instance with the following code: + + U = ACCESS_ONCE(*A); + ACCESS_ONCE(*A) = V; + ACCESS_ONCE(*A) = W; + X = ACCESS_ONCE(*A); + ACCESS_ONCE(*A) = Y; + Z = ACCESS_ONCE(*A); + +and assuming no intervention by an external influence, it can be assumed that +the final result will appear to be: + + U == the original value of *A + X == W + Z == Y + *A == Y + +The code above may cause the CPU to generate the full sequence of memory +accesses: + + U=LOAD *A, STORE *A=V, STORE *A=W, X=LOAD *A, STORE *A=Y, Z=LOAD *A + +in that order, but, without intervention, the sequence may have almost any +combination of elements combined or discarded, provided the program's view of +the world remains consistent. Note that ACCESS_ONCE() is -not- optional +in the above example, as there are architectures where a given CPU might +reorder successive loads to the same location. On such architectures, +ACCESS_ONCE() does whatever is necessary to prevent this, for example, on +Itanium the volatile casts used by ACCESS_ONCE() cause GCC to emit the +special ld.acq and st.rel instructions that prevent such reordering. + +The compiler may also combine, discard or defer elements of the sequence before +the CPU even sees them. + +For instance: + + *A = V; + *A = W; + +may be reduced to: + + *A = W; + +since, without either a write barrier or an ACCESS_ONCE(), it can be +assumed that the effect of the storage of V to *A is lost. Similarly: + + *A = Y; + Z = *A; + +may, without a memory barrier or an ACCESS_ONCE(), be reduced to: + + *A = Y; + Z = Y; + +and the LOAD operation never appear outside of the CPU. + + +AND THEN THERE'S THE ALPHA +-------------------------- + +The DEC Alpha CPU is one of the most relaxed CPUs there is. Not only that, +some versions of the Alpha CPU have a split data cache, permitting them to have +two semantically-related cache lines updated at separate times. This is where +the data dependency barrier really becomes necessary as this synchronises both +caches with the memory coherence system, thus making it seem like pointer +changes vs new data occur in the right order. + +The Alpha defines the Linux kernel's memory barrier model. + +See the subsection on "Cache Coherency" above. + + +============ +EXAMPLE USES +============ + +CIRCULAR BUFFERS +---------------- + +Memory barriers can be used to implement circular buffering without the need +of a lock to serialise the producer with the consumer. See: + + Documentation/circular-buffers.txt + +for details. + + +========== +REFERENCES +========== + +Alpha AXP Architecture Reference Manual, Second Edition (Sites & Witek, +Digital Press) + Chapter 5.2: Physical Address Space Characteristics + Chapter 5.4: Caches and Write Buffers + Chapter 5.5: Data Sharing + Chapter 5.6: Read/Write Ordering + +AMD64 Architecture Programmer's Manual Volume 2: System Programming + Chapter 7.1: Memory-Access Ordering + Chapter 7.4: Buffering and Combining Memory Writes + +IA-32 Intel Architecture Software Developer's Manual, Volume 3: +System Programming Guide + Chapter 7.1: Locked Atomic Operations + Chapter 7.2: Memory Ordering + Chapter 7.4: Serializing Instructions + +The SPARC Architecture Manual, Version 9 + Chapter 8: Memory Models + Appendix D: Formal Specification of the Memory Models + Appendix J: Programming with the Memory Models + +UltraSPARC Programmer Reference Manual + Chapter 5: Memory Accesses and Cacheability + Chapter 15: Sparc-V9 Memory Models + +UltraSPARC III Cu User's Manual + Chapter 9: Memory Models + +UltraSPARC IIIi Processor User's Manual + Chapter 8: Memory Models + +UltraSPARC Architecture 2005 + Chapter 9: Memory + Appendix D: Formal Specifications of the Memory Models + +UltraSPARC T1 Supplement to the UltraSPARC Architecture 2005 + Chapter 8: Memory Models + Appendix F: Caches and Cache Coherency + +Solaris Internals, Core Kernel Architecture, p63-68: + Chapter 3.3: Hardware Considerations for Locks and + Synchronization + +Unix Systems for Modern Architectures, Symmetric Multiprocessing and Caching +for Kernel Programmers: + Chapter 13: Other Memory Models + +Intel Itanium Architecture Software Developer's Manual: Volume 1: + Section 2.6: Speculation + Section 4.4: Memory Access |